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Rohit’s throw runs Mitchell out in India-New Zealand ODI

Published 4 November 2026

Rohit Sharma’s fielding helped India remove Daryl Mitchell for 28 in the first one-day international against New Zealand, with KL Rahul completing the run-out in the 22nd over at Eden Park on November 4, 2026. Mitchell had faced 41 balls when he pushed the ball into the covers and set off for a single. He hesitated while attempting the run, according to the match account, giving Rohit time to dive and release a throw toward the stumps. Rahul collected it and broke the wicket while Mitchell was short of his crease. The dismissal ended Mitchell’s innings during New Zealand’s effort to build a total. The account described the throw as a direct hit to Rahul, who removed the bails without fumbling. Shubman Gill and Virat Kohli joined Rohit after the run-out. The match account did not report a final score or result. The first ODI opened a five-match series, with India and New Zealand meeting in the 50-over format after India’s T20I series against New Zealand. The contest also marked the return of Rohit and Kohli to ODI action following India’s home series against the West Indies, where both scored centuries, according to reports ahead of the match. The two senior batters were a...

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